2(x-3)^2=2(x^2+9)

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Solution for 2(x-3)^2=2(x^2+9) equation: 



2(x-3)^2=2(x^2+9)

We move all terms to the left:

2(x-3)^2-(2(x^2+9))=0



We calculate terms in parentheses: -(2(x^2+9)), so:

2(x^2+9)

We multiply parentheses

2x^2+18

Back to the equation:

-(2x^2+18)



We get rid of parentheses

-2x^2+2(x-3)^2-18=0

We move all terms containing x to the left, all other terms to the right

-2x^2+2(x-3)^2=18

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